Optimal. Leaf size=198 \[ \frac{\sqrt{a^2+2 a b x+b^2 x^2} \left (4 c d-e^2\right ) (2 a d-b e) \tanh ^{-1}\left (\frac{2 d x+e}{2 \sqrt{d} \sqrt{c+d x^2+e x}}\right )}{16 d^{5/2} (a+b x)}+\frac{\sqrt{a^2+2 a b x+b^2 x^2} (2 d x+e) (2 a d-b e) \sqrt{c+d x^2+e x}}{8 d^2 (a+b x)}+\frac{b \sqrt{a^2+2 a b x+b^2 x^2} \left (c+d x^2+e x\right )^{3/2}}{3 d (a+b x)} \]
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Rubi [A] time = 0.101076, antiderivative size = 198, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 35, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.143, Rules used = {969, 640, 612, 621, 206} \[ \frac{\sqrt{a^2+2 a b x+b^2 x^2} \left (4 c d-e^2\right ) (2 a d-b e) \tanh ^{-1}\left (\frac{2 d x+e}{2 \sqrt{d} \sqrt{c+d x^2+e x}}\right )}{16 d^{5/2} (a+b x)}+\frac{\sqrt{a^2+2 a b x+b^2 x^2} (2 d x+e) (2 a d-b e) \sqrt{c+d x^2+e x}}{8 d^2 (a+b x)}+\frac{b \sqrt{a^2+2 a b x+b^2 x^2} \left (c+d x^2+e x\right )^{3/2}}{3 d (a+b x)} \]
Antiderivative was successfully verified.
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Rule 969
Rule 640
Rule 612
Rule 621
Rule 206
Rubi steps
\begin{align*} \int \sqrt{a^2+2 a b x+b^2 x^2} \sqrt{c+e x+d x^2} \, dx &=\frac{\sqrt{a^2+2 a b x+b^2 x^2} \int \left (2 a b+2 b^2 x\right ) \sqrt{c+e x+d x^2} \, dx}{2 a b+2 b^2 x}\\ &=\frac{b \sqrt{a^2+2 a b x+b^2 x^2} \left (c+e x+d x^2\right )^{3/2}}{3 d (a+b x)}+\frac{\left (b (2 a d-b e) \sqrt{a^2+2 a b x+b^2 x^2}\right ) \int \sqrt{c+e x+d x^2} \, dx}{d \left (2 a b+2 b^2 x\right )}\\ &=\frac{(2 a d-b e) (e+2 d x) \sqrt{a^2+2 a b x+b^2 x^2} \sqrt{c+e x+d x^2}}{8 d^2 (a+b x)}+\frac{b \sqrt{a^2+2 a b x+b^2 x^2} \left (c+e x+d x^2\right )^{3/2}}{3 d (a+b x)}+\frac{\left (b (2 a d-b e) \left (4 c d-e^2\right ) \sqrt{a^2+2 a b x+b^2 x^2}\right ) \int \frac{1}{\sqrt{c+e x+d x^2}} \, dx}{8 d^2 \left (2 a b+2 b^2 x\right )}\\ &=\frac{(2 a d-b e) (e+2 d x) \sqrt{a^2+2 a b x+b^2 x^2} \sqrt{c+e x+d x^2}}{8 d^2 (a+b x)}+\frac{b \sqrt{a^2+2 a b x+b^2 x^2} \left (c+e x+d x^2\right )^{3/2}}{3 d (a+b x)}+\frac{\left (b (2 a d-b e) \left (4 c d-e^2\right ) \sqrt{a^2+2 a b x+b^2 x^2}\right ) \operatorname{Subst}\left (\int \frac{1}{4 d-x^2} \, dx,x,\frac{e+2 d x}{\sqrt{c+e x+d x^2}}\right )}{4 d^2 \left (2 a b+2 b^2 x\right )}\\ &=\frac{(2 a d-b e) (e+2 d x) \sqrt{a^2+2 a b x+b^2 x^2} \sqrt{c+e x+d x^2}}{8 d^2 (a+b x)}+\frac{b \sqrt{a^2+2 a b x+b^2 x^2} \left (c+e x+d x^2\right )^{3/2}}{3 d (a+b x)}+\frac{(2 a d-b e) \left (4 c d-e^2\right ) \sqrt{a^2+2 a b x+b^2 x^2} \tanh ^{-1}\left (\frac{e+2 d x}{2 \sqrt{d} \sqrt{c+e x+d x^2}}\right )}{16 d^{5/2} (a+b x)}\\ \end{align*}
Mathematica [A] time = 0.128185, size = 134, normalized size = 0.68 \[ \frac{\sqrt{(a+b x)^2} \left (2 \sqrt{d} \sqrt{c+x (d x+e)} \left (6 a d (2 d x+e)+b \left (8 c d+8 d^2 x^2+2 d e x-3 e^2\right )\right )+3 \left (4 c d-e^2\right ) (2 a d-b e) \tanh ^{-1}\left (\frac{2 d x+e}{2 \sqrt{d} \sqrt{c+x (d x+e)}}\right )\right )}{48 d^{5/2} (a+b x)} \]
Antiderivative was successfully verified.
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Maple [C] time = 0.202, size = 257, normalized size = 1.3 \begin{align*}{\frac{{\it csgn} \left ( bx+a \right ) }{48} \left ( 16\,{d}^{5/2} \left ( d{x}^{2}+ex+c \right ) ^{3/2}b+24\,{d}^{7/2}\sqrt{d{x}^{2}+ex+c}xa-12\,{d}^{5/2}\sqrt{d{x}^{2}+ex+c}xbe+12\,{d}^{5/2}\sqrt{d{x}^{2}+ex+c}ae-6\,{d}^{3/2}\sqrt{d{x}^{2}+ex+c}b{e}^{2}+24\,\ln \left ( 1/2\,{\frac{2\,\sqrt{d{x}^{2}+ex+c}\sqrt{d}+2\,dx+e}{\sqrt{d}}} \right ) ac{d}^{3}-6\,\ln \left ( 1/2\,{\frac{2\,\sqrt{d{x}^{2}+ex+c}\sqrt{d}+2\,dx+e}{\sqrt{d}}} \right ) a{d}^{2}{e}^{2}-12\,\ln \left ( 1/2\,{\frac{2\,\sqrt{d{x}^{2}+ex+c}\sqrt{d}+2\,dx+e}{\sqrt{d}}} \right ) bc{d}^{2}e+3\,\ln \left ( 1/2\,{\frac{2\,\sqrt{d{x}^{2}+ex+c}\sqrt{d}+2\,dx+e}{\sqrt{d}}} \right ) bd{e}^{3} \right ){d}^{-{\frac{7}{2}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \sqrt{d x^{2} + e x + c} \sqrt{{\left (b x + a\right )}^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.71057, size = 683, normalized size = 3.45 \begin{align*} \left [\frac{3 \,{\left (8 \, a c d^{2} - 4 \, b c d e - 2 \, a d e^{2} + b e^{3}\right )} \sqrt{d} \log \left (8 \, d^{2} x^{2} + 8 \, d e x + 4 \, \sqrt{d x^{2} + e x + c}{\left (2 \, d x + e\right )} \sqrt{d} + 4 \, c d + e^{2}\right ) + 4 \,{\left (8 \, b d^{3} x^{2} + 8 \, b c d^{2} + 6 \, a d^{2} e - 3 \, b d e^{2} + 2 \,{\left (6 \, a d^{3} + b d^{2} e\right )} x\right )} \sqrt{d x^{2} + e x + c}}{96 \, d^{3}}, -\frac{3 \,{\left (8 \, a c d^{2} - 4 \, b c d e - 2 \, a d e^{2} + b e^{3}\right )} \sqrt{-d} \arctan \left (\frac{\sqrt{d x^{2} + e x + c}{\left (2 \, d x + e\right )} \sqrt{-d}}{2 \,{\left (d^{2} x^{2} + d e x + c d\right )}}\right ) - 2 \,{\left (8 \, b d^{3} x^{2} + 8 \, b c d^{2} + 6 \, a d^{2} e - 3 \, b d e^{2} + 2 \,{\left (6 \, a d^{3} + b d^{2} e\right )} x\right )} \sqrt{d x^{2} + e x + c}}{48 \, d^{3}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \sqrt{c + d x^{2} + e x} \sqrt{\left (a + b x\right )^{2}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.21137, size = 250, normalized size = 1.26 \begin{align*} \frac{1}{24} \, \sqrt{d x^{2} + x e + c}{\left (2 \,{\left (4 \, b x \mathrm{sgn}\left (b x + a\right ) + \frac{6 \, a d^{2} \mathrm{sgn}\left (b x + a\right ) + b d e \mathrm{sgn}\left (b x + a\right )}{d^{2}}\right )} x + \frac{8 \, b c d \mathrm{sgn}\left (b x + a\right ) + 6 \, a d e \mathrm{sgn}\left (b x + a\right ) - 3 \, b e^{2} \mathrm{sgn}\left (b x + a\right )}{d^{2}}\right )} - \frac{{\left (8 \, a c d^{2} \mathrm{sgn}\left (b x + a\right ) - 4 \, b c d e \mathrm{sgn}\left (b x + a\right ) - 2 \, a d e^{2} \mathrm{sgn}\left (b x + a\right ) + b e^{3} \mathrm{sgn}\left (b x + a\right )\right )} \log \left ({\left | -2 \,{\left (\sqrt{d} x - \sqrt{d x^{2} + x e + c}\right )} \sqrt{d} - e \right |}\right )}{16 \, d^{\frac{5}{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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